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In a triangle ABC, cos 3A + cos 3B + cos...

In a triangle `ABC, cos 3A + cos 3B + cos 3C = 1`, then then one angle must be exactly equal to

A

`pi/3`

B

`(2pi)/(3)`

C

`pi`

D

`(4pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
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