If cot^(2)x=cot(x-y)*cot(x-z), then cot2...

If `cot^(2)x=cot(x-y)*cot(x-z)`, then `cot2x` is equal to `(x!= pm pi/4)`

A

`1/2 ( tan y + tan z)`

B

`1/2 ( cot y + cot z)`

C

`1/2 (sin y + sin z)`

D

None of these

Verified by Experts

The correct Answer is:

B

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