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(tanA+secA-1)/(tanA-secA+1)=(cosA)/(1-si...

`(tanA+secA-1)/(tanA-secA+1)=(cosA)/(1-sinA)`

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To solve the equation \(\frac{\tan A + \sec A - 1}{\tan A - \sec A + 1} = \frac{\cos A}{1 - \sin A}\), we will follow these steps: ### Step 1: Rewrite the Right Side We start with the right side of the equation: \[ \frac{\cos A}{1 - \sin A} \] We can multiply the numerator and denominator by \(1 + \sin A\) to simplify it: ...
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