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If an elements M has M(avg) = 51.7 find ...

If an elements `M` has `M_(avg) = 51.7` find relative abundances of `.^(50)M` and `.^(52)M` isotopes in nature ? [Assume `M` exists in only two allotropic forms in nature] .

Text Solution

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Let `.^(50)M` isotope be `x%` and `.^(52)M` isotope be `(100 -x) %` in nature
`rArr51.7=M_("avg")=(x)/(100)(50)+(100-x)/(100)(52)rArrx=15% implies 15% .^(50)M`and`85%.^(52)M`in nature .
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