Calculate mass of `Cu` in `3.67 xx 10^(3)g CuFeS_(2)` ? (Atomic mass `Cu = 63.5 Fe = 56,S = 32)` .

Explanation

Molar mass of `CuFeS_(2) = 183.5`
`:'(w_(cu))/(w_(CuFeS_(2)))=` constant
`:.(63.5)/(183.5)=(w_(Cu))/(3.67xx10^(3))rArrw_(Cu)=1270gm` .