Find molality of aqueous solution of `CH_(3)COOH` whose molarity is `2M` and density `d = 1.2g//mL`
`"Hint":m=(M)/(d-MM_(s))xx1000`
Where d = density in `gL^(-1)`, ,M = Molartity, m = molality, `M_(S) =` molar mass of solute .

Explanation

`m=(2)/(1200-2xx60)xx1000=1.85m` .