A solution is made by mixing `300ml 1.5M Al_(2) (SO_(4))_(3) + 300ml 2M CaSO_(4) + 400ml 3.5M CaCl_(2)`
Find final molarity of `(1) SO_(4).^(-2), (2) Ca^(2+)` (3) `Cl^(-)` [Assume complete dissociation of these compound] .

Explanation

`[SO_(4)^(-2)]_(f)=("Totalmoles")/("Totalvolume")=(300 xx 1.5 xx 10^(-3)xx3+300xx2xx10^(3))/((300 +300+400)xx10^(3))=1.95M`
(2) `[Ca^(+2)]_(f)=(300xx2+400xx3.5)/(1000)=2M`
(3) `[Cl]_(f)=(400xx3.5xx2)/(1000)=2.8M` .