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A pure gas that is 14.3% hydrogen and 85...

A pure gas that is `14.3%` hydrogen and `85.7%` carbon by mass has a density of `2.5g L^(-1)` at `0^(@)C` and 1 atm pressure. What is the molecular formula of the gas :

A

`CH_(2)`

B

`C_(2)H_(4)`

C

`C_(4)H_(8)`

D

`C_(6)H_(12)`

Text Solution

Verified by Experts

The correct Answer is:
C

`% "mol Simples ratio"`
`C" " 85.7 " "85.7//12 = 7.14" "7.14// 7.14 = 1 " "1`
`H " "14.3" " 14.3//1 = 14.3" " 14.3//7.14 = 2 " "2`
`:.` Emperical formal `=CH_(2)`
`:. PMw = DRT`
`Mw = (DRT)/(P) = (2.5 xx 0821 xx 273)/(1) =56`
`n = ("molecular wt")/("Ewt") = (56)/(14) = 4`
Molecular formula `= n xx E.F`
`= 4 xx CH_(2)`
`= C_(4) H_(8)` .
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