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The molality of a sulphuric acid solutio...

The molality of a sulphuric acid solution is `0.2"mol"//"kg"` Calculate the total weight of the solution :

A

`1000 mL`

B

`1098.6g`

C

`980.4g`

D

`1019.6g`

Text Solution

Verified by Experts

The correct Answer is:
D
Molality of `H_(2)SO_(4) (H_(2)SO_(4)) = 2mol//kg`
`2 mol H_(2)SO_(4)` then `wt`
`=20xx98 = 19.6 g`
`wt` of solvent `=1kg=1000g`
`wt` of solution `=19.6+ 1000 = 1019.6 g`
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