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The % loss in weight heating a pure samp...

The `%` loss in weight heating a pure sample of potassium chlorate `(M. wt. 122.5)` will be :

A

`12.25`

B

`24.50`

C

`39.17`

D

`49.0`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,KClO_(3)overset(A)rarrKCl+,(2)/(2)O_(2)),(,1mol,(3)/(2)mol),(,1xx122.5 g,(3)/(2)xx32),(,1" "rarr,((3)/(2)xx32)/(122.5)=0.3918):}`
`%` Loss `=0.3918xx100=39.18`
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