A compound has the molecular formula `X_(4)O_(6)`. If `10 g "of" X_(4)O_(6)` has `5.72 g X`, atomic mass of `X` is:

Options

A. `32 "amu"`
B. `37 "amu"`
C. `42 "amu"`
D. `98 "amu"`

Answer

A

Explanation

`X_(4)O_(6)rarrX+3O_(2)`
`4_(X) n_(X)O_(6)=n_(X)`
`4_(X)(10)/(4x+96)=(5.72)/(x)`
`40x = 5.72xx4x+96xx5.72`
`17.12 x = 549.12" "x=32 "amu"`