Equal volume of `10% (v//v)` of `HCI` is mixed with `10%(v//v) NaOH` solution. If density of pure `NaOH` is `1.5` times that of pure `HCl` then the resultant solution be ?

Options

A. basic
B. neutral
C. acidic
D. can't be predicted.

Answer

A

Explanation

`10% (v//v) HCl`
`100ml` contain `10ml HCl`
`10% (v//v) NaOH` i.e. `100ml` contain `10mL NaOH` denisty of `NaOH=1.5` density of `NaOH =1.5` density of `HCl`
`((M)/(V))_(NaOH)= 1.5 ((M)/(V))_(HCl)`
Resultant = Basic