A sample of `H_(2)O_(2)` solution labelled as "28 volume" has density of 265 g/L. Mark the correct option(s) representing concentration of same solution in other units :

Options

A. `M_(H_(2)O_(2)) = 2.5`
B. `%(w)/(v) = 17`
C. `"mole fraction of" H_(2)O_(2)=0.2`
D. `m_(H_(2)O_(2))=13.88`

Answer

A, C, D

Explanation

Molarity
`=(X("volume"))/(11.2) = (28)/(11.2) = 2.5`
`m = (Mxx1000)/(d xx1000-MM_(w))`
`m_(H_(2)O)=13.8`
`2.5 "mole"` in `1 L` solution
`d = 265 g//L`, mass `= 265` solution
`n_(H_(2)O) = 10 = (2.5)/(10+2.5) = 0.2`
`%(w)/(V) = (wt."of solute")/("volume of solution (mL)")`
`= (10xx18)/(1000) xx 100`
`= %(w)/(V)`=18%`