Calculate the mass of sucrose `C_(12)H_(22)O_(11) (s)` produced by mixing `78 g` of `C(s), 11 g` of `H_(2)(g) & 67.2 "litre"` of `O_(2)(g)` at `STP` according to given reaction (unbalanced) ?

Options

A. `171 g`
B. `155.4 g`
C. `185.25 g`
D. None of these

Answer

A

Explanation

`12 C (s)+11 H_(2) (g) + (11)/(2) O_(2) rarr C_(12)H_(22)O_(11)`
`{:(,"mole",(78gm)/(12),(11)/(2),(68.1)/(27.7)),(,,=6.5,5.5,3),(,,,(LR),),(,,,,):}`
mass of `C_(12)H_(22)O_(11) = 0.5 xx 342 = 171 gm`