`H_(2)SO_(4)` solution `(80% "by weight and specific gravity" 1.75 g//ml)` is used to prepare `2 litre` of `0.25 MH_(2)SO_(4)` (aq). The volume of `H_(2)SO_(4)` solution (original) which must be used is :

Options

A. `107.18ml`
B. `43.75ml`
C. `35ml`
D. None of these

Answer

C

Explanation

Let `x ml` of `H_(2)SO_(4)` solution
`(n_(H_(2)SO_(4)))_(i) = (n_(H_(2)SO_(4)))_(i)`
`1.75x xx (80)/(100) = 2xx0.25`
`x = 35 mL`