How much quantity of zinc will have to be reacted with excess of dilute `HCl` solution ti produce sufficient hydrogen gas for completely reacting with the oxygen obtained by decomposing `5.104g` of potassium chlorate?

Answer

`8.124gZn`

Explanation

`1.0` mole of `KClO_(3) -= 3.0` mole of `Zn`
`(5.104)/(122.5)` mole `KClO_(3)=(3xx5.104)/(122.5)`
mol of `Zn = (3xx5.104xx65)/(122.5)=8.124 " "g" " Zn`