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Calculate the radius ratio of 2^(nd) orb...

Calculate the radius ratio of `2^(nd)` orbit of hydrogen and `3^(rd)` orbit of `Li^(+2)`

Text Solution

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Atomic number of `H=1`
Atomic number of `Li=3`
`2^(nd)` orbit radius of hydrogen
`(r_(2))_(H)=0.529xx(2^(2))/(1)`
`3^(rd)` orbit of `Li^(+2)`
`(r_(3))Li^(+2)=0.529xx(3^(2))/(3)`
`because = ((r_(2))_H)/((r_(3))_(Li^(+2)))=(0.529xx(2^(2))/(1))/(0.529xx(3^(2))/(3))=(4)/(3)`
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