Home
Class 11
CHEMISTRY
Find the wavelength of light emitted whe...

Find the wavelength of light emitted when an electron drops from `n=3` level to ground state in `He^(+)` ion Given Rydberg constant `=10^(7)m^(-1)`

Text Solution

Verified by Experts

`bar(upsilon)=(1)/(lamda)=Z^(2)R_(H)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]implies bar(upsilon)=(2)^(2).(10^(7)).[(1)/(1)-(1)/(9)]implies bar(upsilon)=4xx10^(7)[(8)/(9)]`
`implies lambda = (9)/(32)xx10^(-7)m=0.2813xx10^(-7)m=281.3Å`
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the energy in joules requried to shift the electron of the hydrogen atom from the first Bohr orbit to the fifth bohr orbit and what is the wavelength of the light emitted when the electron returns to the ground state ? The ground state electron energy is 2.18 xx 10^(1) ergs

Calculate wavelength of emitted radiation when electron transition from n=3 to n=2 ? This radiation belong to which region.

In electron ….. From infinite state to ground state in H atom . Find the emitted wavelength .

The ionization energy of hydrogen atom in the ground state is 1312 kJ "mol"^(-1) . Calculate the wavelength of radiation emitted when the electron in hydrogen atom makes a transition from n = 2 state to n = 1 state (Planck’s constant, h = 6.626 xx 10^(-34) Js , velocity of light, c = 3 xx 10^8 m s^(-1) , Avogadro’s constant, N_A = 6.0237 xx 10^23 "mol"^(-1) ).

The wavelength of the radiations emitted when in a hydrogen atom electron falls from infinity to stationary state is : (R_H = 1. 097 xx10^7 m^(-1)) .

The spectral line obtained when electron jumps from n_(1) = 6 to n_(2) = 2 state in hydrogen atom belongs to the

Below are shown the energy levels for a particular atom. A photon with wavelength is emitted when the system transist from the fourth energy level (4E) to the first energy level (E). When the system transist from the (7)/(3)E energy level to E energy level photons emitted with wavelength lamda_(2) , then (lamda_(1))/(lamda_(2))=.......