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If the value of E=-78.4 "kcal//mol", the...

If the value of `E=-78.4 "kcal//mol"`, the order of the orbit in hydrogen atom is-

A

`4`

B

`3`

C

`2`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=-78.4 kcal//mol`
`E_(n)=-313.6xx(Z^(2))/(n^(2))kcal//mol`
for `H` atoom `Z=1 " "-78.4=313.6xx(1)/(n^(2))`
`n^(2)=(313.6)/(78.4)" "n=2`
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