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Electronmagnetic radiations having lambd...

Electronmagnetic radiations having `lambda=310Å`are subjected to a metal sheet having work function `=12.8eV`. What will be the velocity of photoelectrons with maximum Kinetic Energy….

A

`0`, no emmision will occur

B

`2.18xx10^(6)m//s`

C

`2.18sqrt(2)xx10^(6)m//s`

D

`8.72xx10^(6)m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
Frequency `=(1)/(T) prop (v)/(T) prop (ƶ//n)/(n^(2)//ƶ)`
Frequency `=(1)/(T) prop (ƶ^(2))/(n^(3))" "Tprop(n^(3))/(ƶ^(2))=(1//4)/(8//1) =(1)/(32)`
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