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The energy of an excited H-atom is -3.4e...

The energy of an excited H-atom is `-3.4eV`. Calculate angular momentum of `e^(-)`

Text Solution

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The correct Answer is:
`h//pi`
Angular momentum `=n((h)/(2pi))`
`((hc)/(lambda))=-3.4eV" "-3.4=-13.6xx(1)^(2)/(n^(2))`
`(-3.4)/(-13.6)=(1)/(n^(2))" "n^(2)=(3.4)/(3.4)`
`n^(2)=4impliesn=2`
`=2((6.626xx10^(-34)xx7)/(2xx22))=(h)/(pi)` or `(6.62xx10^(-39)xx7)/(2)`
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