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A proton is accelerated to one tenth of ...

A proton is accelerated to one tenth of the velocity of light. If its velocity can be measured with a precision `-pm1%`. What must be its uncertainty in position?

Text Solution

Verified by Experts

The correct Answer is:
`1.05xx10^(-13)m`
`(1)/(10)xx3xx10^(8)=DeltaV=3xx10^(7)`
`Deltax xxDeltam xxDeltav=(h)/(4pi)`
`Deltax xx 1.672xx10^(-27)kgxx3xx10^(7)=(6.626xx10^(-34))/(4xx3.14)impliesDeltax=(6.626xx10^(-34)xx100)/(1.672xx10^(-27)xx3xx10^(7)xx4xx314)`
`Deltax=1.05xx10^(-13)m`
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