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The quantum yield for decomposition of ...

The quantum yield for decomposition of HI id 0.2 .In an experiment 0.01 moles of HI are decomposed .
Find the number of photons absorbed.

Text Solution

Verified by Experts

The correct Answer is:
`3xx10^(22)`
`(0.2n)/(Na)=0.01`mole" "`(0.2xxn)/(1+128)=0.01`
`(0.2xxn)/(10xx127)=(1)/(100)" "2xxn=(127)/(10)`
`n=(127)/(10xx2)=(12.7)/(2)=6`
No. of protons `=(6xx10^(22))/(2)=3xx10^(22)`
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