Home
Class 12
CHEMISTRY
The same current if passed through solut...

The same current if passed through solution of silver nitrate and cupric salt connected in series. If the weights of silver deposited is `1.08g`. Calculate the weight of copper deposited

Text Solution

Verified by Experts

According to faradays second law.
`(W_(1))/(W_(2)) = (E_(1))/(E_(2)) rArr (1.08)/(W_(2)) = (108)/(31.75) rArr W_(2) = 0.3175 g`
Promotional Banner

Similar Questions

Explore conceptually related problems

An electric current is passed through three cells in series containing respectively solutions of copper sulphate, silver nitrate and potassium iodide. What weights of silver and iodine will be liberated while 1.25 g of copper is being deposited ?

Two different electrolytic cells filled with molten Cu(NO_3)_2 and molten Al(NO_3)_3 respectively are connected in series. When electricity is passed 2.7 gram Al is deposited on electrode. Calculate the weight of Cu deposited on cathode.

A steady current is passed for 25minutes through a silver voltameter and ammeter in series and 0.059g of silver of deposited. The ammeter reads 0.3A. Find the errror, if any, in the ammeter reading, given that the E.C.E. of silver =11.18xx10^(-7) kg C^(-1) .

3A current was passed through an aqueous solution of an unknown salt of Pd for 1hr. 2.977 g of Pd^(+n) was deposited at cathode. Find n.

A certain metal salt solution is electrolysed in series with a silver coulometer. The weight of silver and the metal deposited are 0.5094g and 0.2653g . Calculate the valency of the metal if its atomic weight is nearly that of silver.

If 50 milli ampere of current is passed through copper coulometer for 60 min, calculate the amount of copper deposited.

If same quantity of electricity is passed through CuCI and CuSO_(4) the ratio of the weights of Cu deposited from CuSO_(4) and CuCI is:-

Two electrolytic cells containing molten solutions of Nickel chloride & Aluminium chloride are connected in series. If same amount of electric current is passed through them, what will be the wright of Nirkel nhtained when 18 gm of Aluminium is obtained? (Al-27 gm/mole, Ni - 58.5 "gm//mole"^(1) )