The equivalenet conductivites of acetic acid at `298K` at the concentration of `0.1M` and `0.001M` are `5.20` and `49.2S cm^(2) eq^(-1)` respectively. Calculate the degree of dissociation of acetic acid at the these concentrations. Given that, `lambda^(prop) (H^(+))` and `lambda^(prop) (CH_(3)COO^(-))` are `349.8` and `40.9 ohm^(-1) cm^(2) mol^(-1)` respectively.

Explanation

Degree of dissocitation is given by `alpha = (lambda^(c))/(lambda^(prop))`
(i) Evaluation of `lambda_(CH_(3)COOH)^(prop)`:
`=40.9 +349.8 = 390.7 ohm^(-1) cm^(2) eq^(-1)`.
(ii) Evaluation of degree of dissociation:
At `C = 0.1M alpha = (lambda^(c))/(lambda^(prop)) = (5.20)/(390.7) = 0.013`
i.e. `1.3%`
At `C = 0.001 M alpha = (lambda^(c))/(lambda^(prop)) = (49.2)/(390.7) = 0.125`
i.e. `12.5%`