For an element 'X' the process of oxidation is:
`X_(2)O_(4)^(-2) rarr` New compound
If `965 A` current when passed for `100` seconds discharged `0.1` of `X_(2)O_(4)^(-2)` find oxidation state of `X` in new compound?

Answer

8

Explanation

`+3`
`X_(2)O_(4)^(-2) rarrX^(+n)`
`:'` oxidation process `3 lt n`
`N`-factor `2(n-3)`
so `0.1 xx 2(n-3) = (i xxt)/(96500) = (965 xx 100)/(96500)`
`2(n-3) = 10`
`n-3 = 5`
`n = 8`