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Emf of a cell corresponding to the react...

Emf of a cell corresponding to the reaction:-
`Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm]` is `0.49V` at `25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V`.
The `pH` of solution in cathode chamber is.

Text Solution

Verified by Experts

The correct Answer is:
5
For given cell
`E = E^(@) -(0.06)/(n)log.([Zn^(2+)]P_(H_(2)))/([H^(+)]^(2))`
`rArr 9 = log 10^(-1) -log [H^(+)]^(2)`
`rArr [H^(+)] = 10^(-5)M`
`pH = 5`
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