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The specific conductance of a N//10 KCI ...

The specific conductance of a `N//10 KCI` solution at `18^(@)C` is `1.12 xx 10^(-2) mho cm^(-1)`. The resistance of the solution contained in the cell is found to be 65 ohms. Calculate the cell constant.

Text Solution

Verified by Experts

The correct Answer is:
9
On further adding `V` volume `0.10 M HCI`, concentration of `NaCI` and `HCI` in the final solution are:
`[NaCI] = (0.05 xx2)/(3) = (1)/(30)M`
`[HCI] = (0.1xx1)/(3) = (1)/(30)M`
Also, since specific conductivity is additive:
`k = K_(NaCI) +K_(HCI)`
`rArr K_(HCI) = 0.017 - 0.0056`
`= 0.0114 S cm^(-1)`
`rArr ^^_(HCI) = (0.0114 xx 1000)/((1)/(30)) = 342 S cm^(2) mol^(-1)`
So ans is `3 +4 +2 = 9`
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