Home
Class 12
CHEMISTRY
Suppose the equilibrium constant for the...

Suppose the equilibrium constant for the reaction,
`3M^(3+) rarr 2M^(2+)(aq) +M^(5+) (aq)`

Text Solution

Verified by Experts

The correct Answer is:
`010`

In aqueous medium is `x x 10^(y)`. Find the value of y from given information.
`E_(M^(5+)//M^(2+))^(@) = 0.6V`
`E_(M^(3+)//M^(2+))^(@) = 0.8V`
`(2.303RT)/(F) = 0.06V`
Promotional Banner

Similar Questions

Explore conceptually related problems

The freezing point depression of a 0.109M aq. Solution of formic acid is -0.21^(@)C . Calculate the equilibrium constant for the reaction, HCOOH (aq) hArr H^(+)(aq) +HCOO^(Theta)(aq) K_(f) for water = 1.86 kg mol^(-1)K

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Find the equilibrium constant at 298K for the reaction, Cu^(2+)(aq) +In^(2+)(aq)hArr Cu^(+)(aq) +In^(3+)(aq) Given that E_(Cu^(2+)//Cu^(+))^(@) =0.15V, E_(In^(3+)//In^(-))^(@) =- 0.42V, E_(In^(2+)//In^(+))^(@) =- 0.40V

Emf of a cell corresponding to the reaction:- Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm] is 0.49V at 25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V . The pH of solution in cathode chamber is.

Starting with 250 ml of Au^(3+) solution 250 ml of Fe^(2+) solution, the following equilibrium is established Au^(3+) (aq) +3Fe^(2+)(aq) hArr 3Fe^(3+) (aq) +Au(s) At equilibrium the equivalents of Au^(3+), Fe^(2+), Fe^(3+) and Au are x,y,z and w respectively. Then: