If `0.4gm` of `NaOH` is present in 60 ml of solution. What is the molarity and normality `[M. wt`. Of `NaOH = 40]`

Explanation

Molarity `=("wt. of solute" xx 1000)/(M. Wt. "of solute" xx "volume of solution" (mL)) = (0.4)/(40 xx 80) xx 1000 = 0.125 M = 0.125 N`