Calculate the molality of `1 L` solution of `93% H_(2)SO_(4)` (Weight/volume) The density of the solution is `1.84 g`.

Explanation

Molarity `= ("Wt.in g" xx "density" xx 1000)/("molecular wt" xx 100) = (93 xx 1.84 xx 1000)/(98 xx 100) = 78.68 M`