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M^(2+) +2e rarr M. 0.275 g of metal M is...

`M^(2+) +2e rarr M. 0.275 g` of metal `M` is deposited at the cathode due to passage of `1A` of current for `965s.` Hence atomic weight of the metal `M` is:-

A

`27.5`

B

`55.0`

C

`110.0`

D

`13.75`

Text Solution

Verified by Experts

The correct Answer is:
B
W = Z I t , `0.275=(at xx14xx965)/(2xx96500)`
`0.550xx100 = at` , at = 55
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