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For Zn^(2+) //Zn, E^(@) =- 0.76, for Ag...

For `Zn^(2+) //Zn, E^(@) =- 0.76`, for `Ag^(+)//Ag, E^(@) = -0.799V`. The correct statement is

A

the reaction `Zn` getting reduced `Ag` getting oxidized is spontaneous

B

`Zn` undergoes reduction and `Ag` is oxidized

C

`Zn` undergoes oxidation and `Ag^(+)` gets reduced

D

No suitable answer

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The correct Answer is:
C
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