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The conductivity of a saturated solution...

The conductivity of a saturated solution of `Ag_(3)PO_(4)` is `9 xx 10^(-6) S m^(-1)` and its equivalent conductivity is `1.50 xx 10^(-4) Sm^(2) "equivalent"^(-1)`. Th `K_(sp)` of `Ag_(3)PO_(4)` is:-

A

`4.32 xx 10^(-18)`

B

`1.8 xx 10^(-9)`

C

`8.64 xx 10^(-13)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda_(eq)+K +(1000)/(N)`
`1.50xx10^(-4)xx10^(4)=9xx10^(-5)xx10^(-2)xx(1000)/(N)`
`N= 6xx10^(-5)`
`S=M=(N)/(n_(f))=(6xx10^(-5))/(3)=2xx10^(-5)mol//L` .
`{:(Ag_(3)PO_(4)=,3 Ag^(+)+,PO_(4)),(,3S,S):}`
`K_(sp)=(3S)^(3).S=27.S^(4)=27xx(2xx10^(-5))^(4)`
`=4.32xx10^(-18)` .
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