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Na-Amalgam is prepared by electrolysis o...

Na-Amalgam is prepared by electrolysis of aq. `NaCI` solution using 10gm Hg cathode. How many Faraday's of electricity is required to prepare `18.7%` Na-Amalgam (current Eff `= 50%)`

A

`0.081`

B

`0.16F`s

C

`0.2F`s

D

`0.1F`

Text Solution

Verified by Experts

The correct Answer is:
C
`((x)/(10+x))xx100=18.7`
`x=2.3` or `0.1` mol
`Na^(+)=2.3` or `0.1` mol
`Na^(+)e^(-)rarr Na-Hg`
`0.2 F(eta = 0.5)`.
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