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The standard reduction potential E^(@) o...

The standard reduction potential `E^(@)` of the following systems are:-
`{:(System,E^(@)("volts")),((i)MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O,1.51),((ii)Sn^(4+)+2e^(-)rarrSn^(2+)0.15,),((iii)Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr2Cr^(3+)+7H_(2)O,1.33),((iv)Ce^(4+)+e^(-)rarrCe^(3+)1.61,):}`
The oxidising power of teh various species decreases in the order

A

`Ce^(4+) gt Cr_(2)O_(7)^(2-) gt Sn^(4+) gt MnO_(4)^(-)`

B

`Ce^(4+)gt MnO_(4)^(-) gt Cr_(2)O_(7)^(2-) gt Sn^(4+)`

C

`Cr_(2)O_(7)^(2-) gt Sn^(4+) gt Ce^(4+) gt MnO_(4)^(-)`

D

`MnO_(4)^(-) gt Ce^(4+) gt Sn^(4+) gt Cr_(2)O_(7)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
B

More the reduction potential stronger the oxidising agent.
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Calculate the equilibrium constant for the reaction: 3Sn(s) +2Cr_(2)O_(7)^(2-) +28 H^(+) rarr 3Sn^(+4) +4Cr^(3+) +14H_(2)O E^(@) for Sn//Sn^(+2) = 0.136 V E^(@) for4 Sn^(2+)//Sn^(4+) =- 0.154V E^(@) for Cr_(2)O_(7)^(2-)//Cr^(3+) = 1.33V

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