Home
Class 12
CHEMISTRY
The e.m.f of the following cell Ni(s)/...

The e.m.f of the following cell
`Ni(s)//NiSO_(4)(1.0M) ||H^(+)(1.0M)|H_(2)(1atm), Pt` at `25^(@)C` is `0.236V`. The electrical energy which can be product is

A

`22.73 kJ`

B

`45.55 kJ`

C

`19.30 kJ`

D

`23.60kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`Ni(s) +2H_(2) rarr NiSO_(4) +H_(2)`
`0.236 = E^(@) - (0.0591)/(n)log.(1)/(1)`
`-nFE^(@) = DeltaG^(@)`
`DeltaG^(@) =- 2 xx 96500 xx 0.236 = 45.55 kJ`
Promotional Banner

Similar Questions

Explore conceptually related problems

The EMF of the cell M|M^(n+)(0.02M) ||H^(+)(1M)|H_(2)(g) (1atm)Pt at 25^(@)C is 0.81V . Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76V .

The emf of a cell corresponding to the reaction Zn +2H^(+)(aq) rarr Zn^(2+) (0.1M) +H_(2)(g) 1 atm is 0.28 volt at 25^(@)C . Calculate the pH of the solution at the hydrogen electrode. E_(Zn^(2+)//Zn)^(@) =- 0.76 volt and E_(H^(+)//H_(2))^(@) = 0

The emf of the cell, Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@) for Ni^(2+)//Ni =- 0.25 volt, E^(@) for Ag^(+)//Ag = 0.80 volt] is given by : [E^(@) for Ag^(+)//Ag = 0.80 volt]

Pt(H_(2))(p_(1))|H^(o+)(1M)|(H_(2))(p_(2)),Pt cell reaction will be exergonic if

The emf of the cell, Pt|H_(2)(1atm)|H^(+) (0.1M, 30mL)||Ag^(+) (0.8M)Ag is 0.9V . Calculate the emf when 40mL of 0.05M NaOH is added.