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The resistance of 0.5M solution of an el...

The resistance of `0.5M` solution of an electrolyte in a cell was found to be `50 Omega`. If the electrodes in the cell are `2.2 cm` apart and have an area of `4.4 cm^(2)` then the molar conductivity (in `S m^(2) mol^(-1))` of the solution is

A

`0.2`

B

`0.02`

C

`0.002`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda_(M) = (K xx100)/(M)`
`k = (1)/(R) ((l)/(a)) = (1)/(5) ((2.2)/(4.4)) = (1)/(100) =0.01`
`lambda_(M) = (0.01 xx 1000)/(0.5) = 20 S cm^(2) "mole"^(-1)`
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