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Specific conductance of pure water at 25...

Specific conductance of pure water at `25^(@)C` is `0.58 xx 10^(-7)` mho `cm^(-1)`. Calculate ionic product of wter `(K_(w))` if ionic conductances of `H^(+)` and `OH^(-)`ions at infinite are `350` and `198` mho `cm^(2)` respectively at `25^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
`0.1934 g//L`
`K_("sol")=1.482 xx 10^(-4)`
`K_(H_(2)O)=1.5 xx 10^(-6)`
`K_("Net/Sol")=1.482 xx 10^(-4) -0.015 xx 10^(-4)`
`=1.467 xx 10^(-4)`
`lamda^(infty)=lamda_(Sr^(2+))^(infty)=59.46 +79.8 =139.26`
`lamda^(infty)=(K xx1000)/(5)`
`S=0.00105 mol/L`
Solubility `= 0.00105 xx 183.6 g//L`
`0.19349 L`.
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