Home
Class 12
CHEMISTRY
Calculate the EMF of a Daniel cell when ...

Calculate the `EMF` of a Daniel cell when the concentartion of `ZnSO_(4)` and `CuSO_(4)` are `0.001M` and `0.1M` respectively. The standard potential of the cell is `1.1V`.

Text Solution

Verified by Experts

The correct Answer is:
`E = 1.1V`

`E_(cell) = E_(ZN//Zn^(2+)) +E_(calomel(Red))`
`E_(ZN//Zn^(2+)) = 0.803`
`E_(cell) = E_(Cu^(2+)//Cu)`
`E_(cell) = 1.1V`
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the pH of "0.001 M HCl" solution

The standard electrode potentials (reduction) of Pt//Fe^(3+),Fe^(+2) and Pt//Sn^(4+),Sn^(+2) are +0.77V and 0.15V respectively at 25^(@)C . The standard EMF of the reaction Sn^(4+) +2Fe^(2+) rarr Sn^(2+) +2Fe^(3+) is

Two students use same stock solution of ZnSO_(4) and a solution of CuSO_(4) . The EMF of one cell is 0.03 higher than the other. The concentration of CuSO_(4) in the cell with higher EMF value is 0.5M . Find the concentration of CuSO_(4) in the other cell. ( Take 2.303 RT//F=0.06)