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Calculate the EMF of a Daniel cell when ...

Calculate the `EMF` of a Daniel cell when the concentartion of `ZnSO_(4)` and `CuSO_(4)` are `0.001M` and `0.1M` respectively. The standard potential of the cell is `1.1V`.

Text Solution

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The correct Answer is:
`E = 1.158V`
`E_(cell) = (E_(cell)^(@) - (0.0591)/(2) log .([Zn^(2+)])/([Cu^(2+)]))`
`= 1.1 -(0.0591)/(2)log.([10^(-3)])/([10^(-1)])`
`= 1.1 +0.0591` ltbr. `=1.1591V`
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