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EMF of the cell Zn ZnSO(4)(a =0.2)||ZnSO...

`EMF` of the cell `Zn ZnSO_(4)(a =0.2)||ZnSO_(4)(a_(2))|Zn` is `-0.0088V` at `25^(@)C`. Calculate the value of `a_(2)`.

Text Solution

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The correct Answer is:
`a_(2) = 0.1006M`
`E_(cell) = (0.0591)/(2)log.([0.2])/([a_(2)])`
`(-0.0088 xx 2)/(0.0591) =- log. ([0.2])/([a_(2)])`
`10^(+0.3) = (0.2)/(a_(2))`
`a_(2) = 0.1006`
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