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The cell Pt, H(2) (1atm) H^(+) (pH =x)| ...

The cell `Pt, H_(2) (1atm) H^(+) (pH =x)|` Normal calomel Electrode has an EMF of `0.67V` at `25^(@)C` .Calculate the pH of the solution. The oxidation potential of the calomel electrode on hydrogen scale is `-0.28V`.

Text Solution

Verified by Experts

The correct Answer is:
`pH = 6.61`
`E_(cell) = E_(cell)^(@) -(0.0591)/(1)log 10^(-x)`
`0.67 =0.28 +(0.0591)/(1) xx x`
`x = 6.61`
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