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The time period of oscillation of a mass...

The time period of oscillation of a mass m suspended from a spring is `2` seconds. If another `2 kg` mass is alos suspended along with m the time period increases by `1` seconds. The value of mass m is

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The correct Answer is:
`Cu =98.88%, Fe = 0.85%`
At cathode only pure copper is deposited so % of
`Cu = (22.011)/(22.26) xx 100 = 98/88%`
Charge passed
`=140 xx 482.5 = 67550` colombs
`= (67550)/(96500) = 0.7` Faraday
Faraday used fot reduction of `Cu =(22.011 xx 2)/(63.5) = 0.69326`
so Farday used for iron `=0.7 - 69326 = 0.00674 F`
mass of iron
`= (0.00674 xx 56)/(2) = 0.1887 g`
`% of Fe = (0.1887)/(22.26) xx 100 = 0.847%`
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