Home
Class 12
CHEMISTRY
Calculate the solubiltit and solubility ...

Calculate the solubiltit and solubility product of `Co_(2) [Fe(CN)_(6)]` is water at `25^(@)C` from the following data: conductivity of a saturated solution of `Co_(2)[Fe(CN)_(6)]` is `2.06 xx 10^(-6) Omega^(-1) cm^(-1)` and that of water used `4.1 xx 10^(-7) Omega^(-1) cm^(-1)`. The ionic molar conductivites of `Co^(2+)` and `Fe(CN)_(6)^(4-)` are `86.0 Omega^(-1)cm^(-1) mol^(-1)` and `44.0 Omega^(-1) cm^(-1) mol^(-1)`.

Text Solution

Verified by Experts

The correct Answer is:
`K_(sp) = 7.682 xx 10^(-7)`
`lambda_(M) = (k xx 1000)/(M)`
`(86 xx 2+444) = ((2.06 xx 10^(-6) -4.1xx10^(-7))xx1000)/(s)`
`s = 2.678 xx 10^(-6)`
`K_(sp) = 4s^(3) = 7.687 xx 10^(-17)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The specific conductivity of a saturated AgCI solution if found to be 2.12 xx 10^(-6)S cm^(-1) and that for water is 6 xx 10^(-8)S cm^(-1) . The solubility of AgCI is: (lambda_(eq)^(prop) = 103 S "equiv"^(-1) cm^(2))

The specific conductance at 25^(@)C of a saturated solution of SrSO_(4) is 1.482 xx 10^(-4) ohm^(-1) cm^(-1) while that of water used is 1.5 xx 10^(-6) mho cm^(-1) . Determine at 25^(@)C the solubility in g per litre of SrSO_(4) in water. molar ionic conductance of Sr^(2+) and SO_(4)^(2-) ions at infinite are 54.46 and 79.8 ohm^(-1) cm^(2) "mole"^(-1) respectively. [Sr = 87.6 S = 32, O =16]

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+))=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solibility of AgCl at 25^(@)C is:

Which of the following have maximum molar conductivity. (i) 0.08M solution and its specific conductivity is 2 xx 10^(-2) Omega^(-1) cm^(-1) (ii) 0.1M solution and its resistivity is 50 Omega cm .

Calculate the dissociation constant of water at 25^(@)C from the following data. Specific conductance of H_(2)O = 5.8 xx 10^(-8) mho cm^(-1), lambda_(H^(+))^(oo) = 350.0 and lambda_(OH^(-))^(oo) = 198.0 mho cm^(2)

The sp cond of a saturated solution of AgCI at 25^(@)C after substractin the sp conductances of conductivity of water is 2.28 xx 10^(-6) mho cm^(-1) . Find the solubility product of AgCI at 25^(@)C(lambda_(AgCI)6(oo) = 138.3 mho cm^(2))