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10 gram of solute with molecular mass 10...

10 gram of solute with molecular mass 100 gram `mol^(-1)` is dissolved in 100 gram solvent to show `0.3^(@)C` elevation in boiling point. The value of molal ebuilioscopic constant will be:

A

10

B

3

C

`0.3`

D

un predictable

Text Solution

Verified by Experts

The correct Answer is:
C
`0.3 = ((1)/(10))/(100) xx 1000 xx k_(b)`
`k_(b) = 0.3`
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