Home
Class 12
CHEMISTRY
The substance A when dissolved in solven...

The substance A when dissolved in solvent B shows the molecular mass corresponding to `A_(3)`. The vant Hoffs factor will be:

A

1

B

2

C

3

D

`1//3`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(3A ,rarr ,A_(3)),(1-alpha,,alpha//3):}`
`i = 1 - alpha +alpha//3 alpha 100%`
`= 1 - 1 +(1)/(3) =(1)/(3)`
Promotional Banner

Similar Questions

Explore conceptually related problems

When a substance is dissolved in a solvent the vapour pressure of solvent decreases. This brings:

0.15 g of a substance dissolved in 15 g of solvent boiled at a temperature higher at 0.216^(@) than that of the pure solvent. Calculate the molecular weight of the substance. Molal elevation constant for the solvent is 2.16^(@)C

If in solvent, n simple molecules of solute combine to form an associated molecule X is degree of association the Van't Hoff's factor 'I' is equal to:

A molecule M associates in a given solvent according to the equation M hArr (M)_(n) . For a certain concentration of M, the van't Hoff factor was found to be 0.9 and the fraction of asscoiated molecules was 0.2 . The value of n is:

10 gram of solute with molecular mass 100 gram mol^(-1) is dissolved in 100 gram solvent to show 0.3^(@)C elevation in boiling point. The value of molal ebuilioscopic constant will be:

Which compound corresponds vant Hoff factor (i) to be equal to 2 in dilute solution: