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The molal boiling point constant of wate...

The molal boiling point constant of water is `0.573^(@)C kg "mole"^(-1)`. When `0.1` mole of glucose is dissolved in `1000g` of water, the solution boils under atmospheric pressure at:

A

`100.513^(@)C`

B

`100.0573^(@)C`

C

`100.256^(@)C`

D

`101.025^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`T - 100 = 0.573 xx 0.1`
`T = 100.0573`
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