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An aqueous solution of NaCI freezes at -...

An aqueous solution of `NaCI` freezes at `-0.186^(@)C`. Given that `K_(b(H_(2)O)) = 0.512K kg mol^(-1)` and `K_(f(H_(2)O)) = 1.86K kg mol^(-1)`, the elevation in boiling point of this solution is:

A

`0.0585 K`

B

`0.0512 K`

C

`1.864 K`

D

`0.0265K`

Text Solution

Verified by Experts

The correct Answer is:
B
`0.186 = 1.86 xm`
`m = 0.1`
`DeltaT_(b) = 0.1 xx 0.512 = 0.0512`
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