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Dry air was passed successively through ...

Dry air was passed successively through a solution of 5g of a solute in 180g of water and then through pure water and then through pure water. The loss in weight of solution was `2.5g` and that of pure solvent `0.04g`. The molecular weight of the solute is:

A

`31.25`

B

`3.125`

C

`312.5`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`(P^(@)-P_(s))/(P_(s)) = ("loss in wt.of solvent")/("loss in wt.of solvent")` ...(i)
`(P^(@)-P_(s))/(P_(s)) = (W_(1))/(M_(1)) xx (M_(2))/(W_(2))` ...(ii)
From equation (i) and (ii)
`(0.04)/(2.5) = (5 xx 18)/(180 xx M_(1))`
`M_(1) = 31.25`
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